(6x^2-5x+9)/(2x-1)

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Solution for (6x^2-5x+9)/(2x-1) equation: 


D( x )

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

x in (-oo:1/2) U (1/2:+oo)

(6*x^2-(5*x)+9)/(2*x-1) = 0

(6*x^2-5*x+9)/(2*x-1) = 0

6*x^2-5*x+9 = 0

6*x^2-5*x+9 = 0

DELTA = (-5)^2-(4*6*9)

DELTA = -191

DELTA < 0

1 = 0

1/(2*x-1) = 0

x belongs to the empty set

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